An A.P. consists of 50terms of which 3rd term is 12 and the last term is 106.Find the 29th term
Given that,
a3 = 12
a50 =106
We know that,
an= a + (n − 1) d
a3 =a + (3 − 1) d
12 = a +2d (I)
Similarly, a50= a + (50 − 1) d
106 = a +49d (II)
On subtracting (I) from(II), we obtain
94 = 47d
d = 2
From equation (I), weobtain
12 = a + 2 (2)
a = 12 − 4= 8
a29 =a + (29 − 1) d
a29 =8 + (28)2
a29 =8 + 56 = 64
Therefore, 29thterm is 64.