MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Third Equation of Motion

An alpha part...

Question

An alpha particle enters a hollow tube of 4m length with an initial speed of 1Km/s. It is accelerated in the tube and comes out of it with a speed of 9Km/s. The time for which it remains inside the tube is

Open in App

Solution

$I n i t i a l v e l o c i t y u = 1 k m / s = 1000 m / s F i n a l v e l o c i t y v = 9 k m / s = 9000 m / s l e n g t h o f t h e t u b e w i l l b e e q u a l t o t h e d i s \tan c e t r a v e l l e d i n t i m e t . v^{2} - u^{2} = 2 a s 9000^{2} - 1000^{2} = 2 a \times 4 a = 10^{7} m / s^{2} v = u + a t t = \frac{v - u}{a} t = \frac{9000 - 1000}{10^{7}} t = 8 \times 10^{- 4} t = 80 m s$

Suggest Corrections

thumbs-up

1

Similar questions

Q. An alpha particle enters a hollow tube of 4 m length with an initial speed of

1 \frac{k m}{s}

. It is accelerated in the tube and comes out of it with a speed of

9 \frac{k m}{s}

. The time for which it remains inside the tube is

Q. An alpha particle enters a hollow tube of 4 m length with an initial speed of

1 \frac{k m}{s}

. It is accelerated in the tube and comes out of it with a speed of

9 \frac{k m}{s}

. The time for which it remains inside the tube is

Q. Initial speed of an alpha particle side a tube a length

4 m

1 k m / s

, if it is accelerated in the tube and comes out with a speed of

9 k m / s

, then the time for which the particle remains inside the tube is

Q. A charged particle travels along the inside of a straight hollow tube

2.0

metre long. The particle is uniformly accelerated. What is the time spent by the particle in the tube if it enters at a speed of

1000

m s and leaves at

9000

Q. Water enters through an end A with speed

v_{1}

and leaves through end B with speed of

v_{2}

of a cylindrical tube AB. The tube is always filled completely with water. In case

I

tube is horizontal, in case

I I

it is vertical with end A upwards and in case

I I I

it is vertical with end B upwards. We have

v_{1} = v_{2}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Third Equation of Motion

PHYSICS

Watch in App

explore_more_icon

Explore more

Third Equation of Motion

Standard IX Physics

Join BYJU'S Learning Program

CrossIcon