An alpha particle is accelerated through a potential difference of 106 volt- Its kinetic energy will be-a- 1 MeV nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -b- 2 MeV nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -c- 4 MeV nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- -d- 8 MeV-

Dear student , Here in this case the kinetic energy is , K.E=2 #215;charge #160;of #160;electron #215;106V=2 #215;e #215;106 #160;V=2 #160;MeV R ...

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Byju's Answer

Standard XII

Physics

Braking Radiation

An alpha part...

Question

An alpha particle is accelerated through a potential difference of 10⁶ volt. Its kinetic energy will be

(a) 1 MeV (b) 2 MeV (c) 4 MeV (d) 8 MeV

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Solution

Dear student ,
Here in this case the kinetic energy is ,
$K . E = 2 \times c h a r g e o f e l e c t r o n \times 10^{6} V = 2 \times e \times 10^{6} V = 2 M e V$
Regards

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An alpha particle is accelerated through a potential difference of 106 volt. Its kinetic energy will be (a) 1 MeV (b) 2 MeV (c) 4 MeV (d) 8 MeV

Dear student , Here in this case the kinetic energy is , K.E=2×charge of electron×106V=2×e×106 V=2 MeV Regards

An alpha particle is accelerated through a potential difference of 10⁶ volt. Its kinetic energy will be

(a) 1 MeV (b) 2 MeV (c) 4 MeV (d) 8 MeV

Dear student ,
Here in this case the kinetic energy is ,
$K . E = 2 \times c h a r g e o f e l e c t r o n \times 10^{6} V = 2 \times e \times 10^{6} V = 2 M e V$
Regards