Question

an athlete takes 5 rounds of a rectangular park , 50 m long and 250 dm wide. then the total distance covered by him?

Answer 1

$$\begin{gathered} \mathrm{Length}\mathrm{of}\mathrm{the}\mathrm{rectangular}\mathrm{park}=50\mathrm{m} \\ \mathrm{Breadth}\mathrm{of}\mathrm{the}\mathrm{rectangular}\mathrm{park}=250\mathrm{dm}=\frac{250}{10}\mathrm{m}=25\mathrm{m}\left[\mathrm{as},1\mathrm{m}=10\mathrm{dm}\right] \\ \mathrm{perimeter}\mathrm{of}\mathrm{the}\mathrm{park}=2\left(\mathrm{length}+\mathrm{breadth}\right)=2\left(50+25\right)=2\times 75=150\mathrm{m} \\ \mathrm{So},\mathrm{distance}\mathrm{covered}\mathrm{in}1\mathrm{round}=150\mathrm{m} \\ \mathrm{so},\mathrm{distance}\mathrm{covered}\mathrm{in}5\mathrm{rounds}=5\times 150=750\mathrm{m} \end{gathered}$$