an electric dipole of dipole moment 20 *10^-6Cm is enclosed by a closed surface .what is the net flux coming out of the surface?

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Solution

The net flux through a surface can be found by considering a closed Gaussian surface enclosing the charges. The flux is equal to the net charge divided by Îµ₀.
In the question, the enclosed by a Gaussian surface due to the dipole is = +q + (-q) = 0
Therefore, the flux is, Ï• = 0/Îµ₀ = 0

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