An element has electronic configuration [Ar] 3d4 in its +3 oxidation state.What will be the electronic configuration of its atom?

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Solution

We are given that the electronic configuration of the element in +3 oxidation state is [Ar]3d⁴. Thus, the atomic number of the element should be
= atomic number of argon + 4 +3
= 18 + 4 + 3
= 25
Thus, the element is manganese and its electronic configuration is [Ar]4s²3d⁵.

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Similar questions

An element has $[A r] 3 d^{4}$ configuration in its +3 oxidation state. The atomic number of element is:

[A r] 3 d^{4}

X

[A r] {3 d}^{4}

+ 3

(A r) 3 d^{3}

(A r) 3 d^{3}

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