An object is placed at a distance of 20cm in front of a convex mirror of radius of curvature 30cm. Find the position and nature of the image.

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Solution

$u = - 20 c m f = C / 2 = 15 c m m i r r o r f o r m u l a 1 / f = 1 / v + 1 / u g e t v a s = 8.57142 c m m = - v / u = 0.42 v i r t u a l, e r e c t, d i m i n i s h e d$

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An object is placed at a distance of 20cm in front of a convex mirror of radius of curvature 30cm. Find the position and nature of the image.

u= -20 cmf= C/2 = 15cmmirror formula 1/f = 1/v +1/uget v as= 8.57142 cmm= -v/u = 0.42virtual, erect, diminished

$u = - 20 c m f = C / 2 = 15 c m m i r r o r f o r m u l a 1 / f = 1 / v + 1 / u g e t v a s = 8.57142 c m m = - v / u = 0.42 v i r t u a l, e r e c t, d i m i n i s h e d$