An object of mass 500 g is immersed into a measuring jar containing water. The initial level of water in te measuring jar is 50 cc. Due to the immersion of the object the water level in the measuring jar reaches to 100 cc. Calculate the mass of the water displaced due to the immersion of the object.

Open in App

Solution

Initially the volume of water in jar was 50 cc, after submerging the object the volume raised was 100 cc. Thus, the volume of water displaced was,
$V = 100 c c - 50 c c V = 50 c c$
On converting the cubic centimetre into cubic metre we get,
$V = 50 \times 10^{- 6} m^{3} V = 5.0 \times 10^{- 5} m^{3}$
Now, we know that the density of the fresh water is, $ρ = 1000 k g / m^{3}$
Thus, the mass of water displaced will be calculated as,
$m a s s o f w a t e r d i s p l a c e d = V o l u m e o f d i s p l a c e d w a t e r \times d e n s i t y o f w a t e r$
On substituting the values we get,
$m = (5.0 \times 10^{- 5} m^{3}) \times (1000 k g / m^{3}) m = 0.05 k g$
or,
$m = 0.05 \times 1000 g r a m s m = 50 g r a m s$
Thus, the mass of water displaced is $m = 50 g r a m s$

Suggest Corrections

Similar questions

Q. The volume of water in a measuring jar is 37 ml. When an object is immersed in the water, the water level rises to 45 ml. What is the volume of the object(in cu cm)?

A body of volume $100 c c$ is immersed completely in water contained in a jar. The weight of water and the jar before immersion of the body was $700 g w t$ . After immersion weight of water and jar will be

Q. Two identical lead bells are immersed into a measuring jar containing water, the level of water raises from

26

^{3}

to 38 cm

^{3}

. If one of the above lead ball and another metallic ball is immersed simultaneously than the level of water in measuring jar rise from

28

^{3}

to 36 cm

^{3}

. Find the volume of the lead ball and metallic ball.

Q. Two identical lead balls are immersed into a measuring jar containing water, the level of water raises from 26 cm

^{3}

to 38 cm

^{3}

. If one of the above lead ball and another metallic ball are immersed simultaneously than level of water in measuring jar rises from 26 cm

^{3}

to 36 cm

^{3}

. Find the volume of the lead ball and metallic ball.

Q. The volume of water in a measuring jar is 15 mL. When a stone is immersed in the water, the water level rises to 20 mL. The volume of the stone is .

Join BYJU'S Learning Program