Question

an object starting from rest attains a speed of 25m/s after travelling a distance of 50 m. calculate the accelaration produced and the total time taken to cover that distance.

Answer 1

Here, initial speed, $u=0$
Final speed, $v=25m/s$
Distance travelled, $s=50m$
Acceleration, $a=?$
Time taken, $t=?$

Now, using the third equation of motion, we get
$$\begin{gathered} v^2=u^2+2as \\ {25}^2=0+2\times a\times 50 \\ or,a=6.25m/s^2 \end{gathered}$$

Now, using the first equation of motion, we get
$$\begin{gathered} v=u+at \\ 25=0+6.25\times t \\ or,t=4s \end{gathered}$$