P and Q are mid point of sides RS & RT respectively of $△$ RST.
PQ = $5 c m$ , RS = RT = $10 c m$ , then perimeter of $△$ RST is:

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Solution

The correct option is D $30$ cm
PQ = 5 cm, & RS = RT, then PQ = $\frac{1}{2}$ ST
( $∵$ P & Q are takes of RS & RT)
and line joining two mid points of the side of triangle is half the third side.
$∴ S T = 10 c m$
perimeter of $△ R S T = R S + S T + T R = 10 + 10 + 10 = 30 c m$

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P and Q are mid point of sides RS & RT respectively of △ RST.PQ = 5cm, RS = RT = 10cm, then perimeter of △RST is:

The correct option is D 30 cmPQ = 5 cm, & RS = RT, then PQ = 12 ST(∵ P & Q are takes of RS & RT)and line joining two mid points of the side of triangle is half the third side.∴ST=10cmperimeter of △RST=RS+ST+TR=10+10+10=30cm

P and Q are mid point of sides RS & RT respectively of $△$ RST.
PQ = $5 c m$ , RS = RT = $10 c m$ , then perimeter of $△$ RST is:

The correct option is D $30$ cm
PQ = 5 cm, & RS = RT, then PQ = $\frac{1}{2}$ ST
( $∵$ P & Q are takes of RS & RT)
and line joining two mid points of the side of triangle is half the third side.
$∴ S T = 10 c m$
perimeter of $△ R S T = R S + S T + T R = 10 + 10 + 10 = 30 c m$