Question

$P$ and $Q$ are the points on the sides $DE$ and $DF$ of a triangle $DEF$ such that $DP=5cm,DE=15cm,DQ=6cm$ and $QF=18cm$, then $PQ\parallel EF$. Is it true?If true enter 1 else 0.

Answer 1

$\frac{DP}{PE}=\frac{5}{15-5}=\frac{1}{2};\frac{DQ}{QF}=\frac{6}{18}=\frac{1}{3}$
As $\frac{DP}{PE}\ne \frac{DQ}{QF}$, therefore $PQ$ is not parallel to $EF$.