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Mole Concept and Avogadro's Number

P and Q are t...

Question

P and Q are two elements which form $P_{2} Q_{3}$ and $P Q_{2}$ . If $0.15$ mole of $P_{2} Q_{3}$ weighs $15.9$ g and $0.15$ mole of $P Q_{2}$ weighs $9.3$ g. The atomic mass of Q is

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Solution

Suppose atomic masses of P and Q are X and Y respectively.
Molar mass of $P_{2} Q_{3} = 2 X + 3 Y$
and Molar mass of $P Q_{2} = X + 2 Y$
Now $M o l e = \frac{m a s s}{m o l a r m a s s}$
$∴ 2 X + 3 Y = 15.9 / 0.15 . . . . (i)$
and $X + 2 Y = 9.3 / 0.15 . . . . (i i)$
Solving these equations, we get $X = 2.6 g {m o l}^{- 1}, Y = 18 g {m o l}^{- 1}$
So, atomic mass of Q is $18$ .

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