X and Y are two elements which form X₂Y₃and XY₂ molecules. If 0.15 mole of X₂Y₃ and XY₂ weighs 15.9 g and 9.3 g respectively. What are the atomic mass of X and Y.

Q. Elements

A

and

B

form two compounds

B_{2} A_{3}

and

B_{2} A

0.05

moles of

B_{2} A_{3}

weight

9.0 g

and

0.10

mole of

B_{2} A

weight

10 g

atomic weight of

A

and

B

are:

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P and Q are two elements which form P2Q3 and PQ2. If 0.15 mole of P2Q3 weight 15.9 g and 0.15mole of PQ2 weight 9.3 g. what are atomic weights of P and Q respectively?

The correct option is C 26 and 18Using- no. of mole =weightmolecular weightP2Q3⇒ 2P+3Q=15.9/0.15=106....(1)PQ2⇒P+2Q=9.3/0.15=62........(2) On solving eqn. (1) & (2) we get- P=26,Q=18

P and Q are two elements which form $P_{2} Q_{3}$ and ${P Q}_{2}$ . If 0.15 mole of $P_{2} Q_{3}$ weight 15.9 g and 0.15mole of ${P Q}_{2}$ weight 9.3 g. what are atomic weights of P and Q respectively?

The correct option is C 26 and 18
Using- no. of mole $= \frac{weight}{molecular weight}$

$P_{2} Q_{3} \Rightarrow$ $2 P + 3 Q = 15.9 / 0.15 = 106$ ....(1)

$P Q_{2} \Rightarrow$ $P + 2 Q = 9.3 / 0.15 = 62$ ........(2)

On solving eqn. (1) & (2) we get-

$P = 26, Q = 18$