    Question

# P and Q be the points of trisection of the line segment joining points A(2,-2) and B(-7,4) such that P is nearer to A. Then coordinates of P and Q are

A
P(-4,2), Q(-1,0)
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B
P(-1,0), Q(-4,2)
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C
P(-2,0), Q(-3,2)
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D
P(-4,-1), Q(2,0)
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Solution

## The correct option is B P(-1,0), Q(-4,2)P and Q are the points of trisection of AB, therefore AP = PQ = QB. Thus, P divides AB internally in the ratio 1:2 and Q divides AB internally in the ratio 2:1. P=(1×(−7)+2×(2)1+2,1×(4)+2×(−2)1+2) =(−7+43,4−43) =(−33,03) =(−1,0) Q=(2×(−7)+1×(2)2+1,2×(4)+1×(−2)2+1) =(−14+23,8−23) =(−123,63) =(−4,2)  Suggest Corrections  1      Similar questions  Related Videos   Representing Equation on Cartesian Plane
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