Question

P and Q start running simultaneously - one from point A to B and the second from point B to A. P's speed is $\frac{6}{5}th$ of Q's speed. If after crossing Q, P takes 2 $\frac{1}{2}h$ to reach B, how much time does Q take to reach A after crossing P?

• A. 3 hours 36 min
• B. 3 hours 48 min
• C. 4 hours 12 min
• D. None of these

Answer 1

The correct option is A 3 hours 36 min

Speed ratio for P and Q = 6:5
Ratio of distance covered before meeting = 6:5
Let total distance be 11 km.
For P after meeting, Distance = 5 km, time = 2.5 hours. So, speed = $\frac{5}{2.5}$ kmph = 2 kmph
Speed of Q = $\frac{5}{6}\times 2$ = 1.67 kmph
Time taken by Q to reach A after meeting = $\frac{6}{1.67}$ = 3.6 hours = 3 hours 36 mins