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Question

Anelectrical technician requires a capacitance of 2 µF in acircuit across a potential difference of 1 kV. A large number of 1 µFcapacitors are available to him each of which can withstand apotential difference of not more than 400 V. Suggest a possiblearrangement that requires the minimum number of capacitors.

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Solution

Total requiredcapacitance, C = 2 µF

Potentialdifference, V= 1 kV = 1000 V

Capacitanceof each capacitor, C1= 1µF

Eachcapacitor can withstand a potential difference, V1= 400 V

Suppose a number ofcapacitors are connected in series and these series circuits areconnected in parallel (row) to each other. The potential differenceacross each row must be 1000 V and potential difference across eachcapacitor must be 400 V. Hence, number of capacitors in each row isgiven as

Hence, there are threecapacitors in each row.

Capacitance of each row

Letthere are nrows, each having three capacitors, which are connected in parallel.Hence, equivalent capacitance of the circuit is given as

Hence,6 rows of three capacitors are present in the circuit. A minimum of 6×3 i.e., 18 capacitors are required for the given arrangement.


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