Question

ANKITESH AND HIS FRIEND JIMMY SOLD TICKETS FOR A CHARITY SHOW FOR RS 3800. IF ANKITESH SOLD IT AT A PRICE WHICH IS 1 38TIMES OF THE PRICE AT WHICH JIMMY SOLD IT ,HOW MUCH DID EACH OF THEM SELL THE TICKETS FOR?

Answer 1

As per my interpretation, it is given that Ankitesh sold it at a price which is $1\frac{3}{8}$ times of the price at which Jimmy sold it.
Suppose Jimmy sold the ticket at Rs.x
Then the price of the ticket sold by Ankitesh = $1\frac{3}{8}x=\frac{11}{8}x$
So total price of the ticket sold by Jimmy and Ankitesh = $x+\frac{11x}{8}=\mathrm{Rs}.3800$
$$\begin{gathered} \Rightarrow \frac{19x}{8}=3800 \\ \Rightarrow x=\frac{3800\times 8}{19}=1600 \end{gathered}$$
Therefore the price of ticket sold by Jimmy = Rs.1600
And the price of the ticket sold by Ankitesh = $\frac{11}{8}\times 1600=\mathrm{Rs}.2200$