wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Aparallel plate capacitor is to be designed with a voltage rating 1kV, using a material of dielectric constant 3 and dielectric strengthabout 107Vm−1.(Dielectric strength is the maximum electric field a material cantolerate without breakdown, i.e., without starting to conductelectricity through partial ionisation.) For safety, we should likethe field never to exceed, say 10% of the dielectric strength. Whatminimum area of the plates is required to have a capacitance of 50pF?

Open in App
Solution

Potential rating of aparallel plate capacitor, V = 1 kV = 1000 V

Dielectric constant ofa material, =3

Dielectric strength =107 V/m

For safety, the fieldintensity never exceeds 10% of the dielectric strength.

Hence, electric fieldintensity, E = 10% of 107 = 106 V/m

Capacitance of theparallel plate capacitor, C = 50 pF = 50 ×10−12 F

Distance between theplates is given by,

Where,

A = Area of eachplate

= Permittivity of free space =

Hence, the area of eachplate is about 19 cm2.


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Idea of Capacitance
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon