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Question

Aparallel plate capacitor is to be designed with a voltage rating 1kV, using a material of dielectric constant 3 and dielectric strengthabout 107Vm−1.(Dielectric strength is the maximum electric field a material cantolerate without breakdown, i.e., without starting to conductelectricity through partial ionisation.) For safety, we should likethe field never to exceed, say 10% of the dielectric strength. Whatminimum area of the plates is required to have a capacitance of 50pF?

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Solution

Potential rating of aparallel plate capacitor, V = 1 kV = 1000 V

Dielectric constant ofa material, =3

Dielectric strength =107 V/m

For safety, the fieldintensity never exceeds 10% of the dielectric strength.

Hence, electric fieldintensity, E = 10% of 107 = 106 V/m

Capacitance of theparallel plate capacitor, C = 50 pF = 50 ×10−12 F

Distance between theplates is given by,

Where,

A = Area of eachplate

= Permittivity of free space =

Hence, the area of eachplate is about 19 cm2.


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