apoorva throws 2 dice ones,and computes the product of the numbers appearing on the dice.Now, Rihu throws 1 dice and squares the number that appears,who has better chance of getting the number 36.why?
Since Apporva throws two dice, total number of outcomes are 36. Therefore, probability of getting 36 by Apporva is (1/36).
On other hand Rihu throws one die, so total number of outcomes are 6. Therefore, probability of getting 36 by Rihu is (1/6).
Hence Rihu has a better chance of getting the number 36.