at what angle a projectile be projected to obtain the maximum horizontal range ?

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Solution

At angle of projection equal to 45 degree, horizontal range is maximum.
$R = \frac{u^{2} \sin 2 θ}{g} r a n g e i s m a x i m u m w h e n θ = 45 d e g r e e$

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at what angle a projectile be projected to obtain the maximum horizontal range ?

At angle of projection equal to 45 degree, horizontal range is maximum. R = u2sin2θgrange is maximum when θ = 45 degree

At angle of projection equal to 45 degree, horizontal range is maximum.
$R = \frac{u^{2} \sin 2 θ}{g} r a n g e i s m a x i m u m w h e n θ = 45 d e g r e e$