balance the equation :- Cu + HNO3 = Cu(NO3)2 + NO H2O
Dear student!
In case of ,
Cu + HNO3 -> Cu(NO3)2 + NO2 + H2O
Here, Cu is in 0 oxidation state which oxidizes to +2 in Cu(NO3)2 while N exists in +5 O.S in HNO3 and reduced to +4 in NO2 the reaction involved is:
Cu + 2e- -> Cu+2
Similarly, N+5 ->N+4 + 1e-
Now the no. of electrons is balanced as :
[Cu0 ->Cu+2 + 2e- ] x1
[N+5 + 1e- -> N+4]x2
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Cu + 2 N+5 -> Cu+2 + 2N+4
Putting the values in molecular form as:
Cu + 2HNO3 -> Cu(NO3)2 + 2NO2
Now, rest molecules are adjusted and filled as; Cu + 2HNO3 -> Cu(NO3)2 + 2NO2 +H2O
Further the no. of atoms are balanced genuinely as ;
Cu + 4HNO3 -> Cu(NO3)2 + 2NO2 + 2H2O