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Question

balance the equation :- Cu + HNO3 = Cu(NO3)2 + NO H2O

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Solution

Dear student!

In case of ,

Cu + HNO3 -> Cu(NO3)2 + NO2 + H2O

Here, Cu is in 0 oxidation state which oxidizes to +2 in Cu(NO3)2 while N exists in +5 O.S in HNO3 and reduced to +4 in NO2 the reaction involved is:

Cu + 2e- -> Cu+2

Similarly, N+5 ->N+4 + 1e-

Now the no. of electrons is balanced as :

[Cu0 ->Cu+2 + 2e- ] x1

[N+5 + 1e- -> N+4]x2

------------------------------------

Cu + 2 N+5 -> Cu+2 + 2N+4

Putting the values in molecular form as:

Cu + 2HNO3 -> Cu(NO3)2 + 2NO2

Now, rest molecules are adjusted and filled as; Cu + 2HNO3 -> Cu(NO3)2 + 2NO2 +H2O

Further the no. of atoms are balanced genuinely as ;

Cu + 4HNO3 -> Cu(NO3)2 + 2NO2 + 2H2O


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