Question

balance the equation in descriptive method :-

sodium + water ----> sodium hydroxide + hydrogen

Answer 1

Descriptive method of the reaction is given as under:-

Na + H₂O --------> NaOH + H₂

Step1) Number of hydrogens on the left hand side is two while on the right hand side it is three so, after multiplying H₂O by two and also right hand side of NaOH by two we get equal number of hydrogens on both the sides.

Now reaction becomes as

Na +2 H₂O --------> 2 NaOH + H₂

Step2) Now number of sodium atom on the left side is one while on the right side it is two so multiply Na atom of left side by 2.

Reaction becomes

2 Na +2 H₂O --------> 2 NaOH + H₂

While number of oxygen atoms on both the sides are equal.

Hope you got it!