Balance the following redox reactions by ion exchange method briefly -Cr-OH-4- -H2O2 - gt- CrO42- - H2O -Basic Medium-MnO4- - C2H2O4 - gt- Mn2- - nbsp-CO2 - H2O - Acidic Medium-

Cr(OH)4 +H2O2+ 2OH – #62; CrO4 2 +4H2OMnO4 +5C2H2O4 +16H+– #62; 2Mn2+ + 10CO2 +8H2O ...

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Wurtz Halide Reaction

Balance the f...

Question

Balance the following redox reactions by ion exchange method briefly .
Cr(OH)₄^- +H₂O₂ --> CrO₄^2- + H₂O (Basic Medium)
MnO₄^- + C₂H₂O₄ --> Mn²⁺ + CO₂ + H₂O ( Acidic Medium)

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M n O_{4}^{-} (a q) + S O_{2} (g) \to M n^{2 +} (a q) + H S O_{4}^{-} (a q)

{M n O_{4}}^{-} + H^{+} + H_{2} O_{2} \to M n^{2 +} + H_{2} O + O_{2}

Balance the following redox reactions by ion-electron method:

(a) (aq) + I^– (aq) → MnO₂ (s) + I₂(s) (in basic medium)

(b) (aq) + SO₂ (g) → Mn²⁺ (aq) + (aq) (in acidic solution)

(d) + SO₂(g) → Cr³⁺ (aq) + (aq) (in acidic solution)

{M n O_{4}}^{-} + {C_{2} O_{4}}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O

K_{3} F e (C N)_{6} + C r_{2} O_{3} + K O H \to K_{4} F e (C N)_{6} + K_{2} C r O_{4} + H_{2} O

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