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Ball A is dro...

Question

Ball A is dropped from a 44.1m high cliff. Two seconds later, another Ball B is thrown downwards from the same place with some initial speed. The two balls reached the ground together. Find the speed with which the ball B was thrown.

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Solution

time take by first ball to reach the ground
use eqn of motion s=ut+at²/2,u=0,s=44.1m,a=9.8m/s²
44.1=9.8t²/2
t=3sec
time taken by second ball =3-2=1sec
now we find initial velocity for second ball
use eqn of motion s=ut+at²/2
44.1=u(1)+9.8(1)²/2
u=39.3m/s

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