barium chloride crystals contain 14.8% water of crystallisation.find the number of molecules of water of crystallisation per molecule.
Calculate Mol. Wt of BaCl2 = 208 g (unhydrated)
Gms of water of hydration is 14.8 % of total hydrated weight
i.e. 14.8/100 = 100X / (208+X) where X = mass of water
= 0.148 = X/(208+X)
= 0.148 x (208+X) = X
Solving for X we get
X = 36.2 g
i.e. 36.2 g of water
Mol wt of water = 18 therefore there are 2 moles of water
Hydrated Barium chloride = BaCl2.2H2O