Question

barium chloride reacts with sodium sulphate to form barium sulphate and sodium chloride, in an experiment to verify the law of conservation of mass 20.8g of barium chloride reacted with 14.2g of sodium sulphate to form 11.7g of sodium chloride. the amount of barium sulphate formed in the above reaction will be : -

(a) 35.0g

(b) 23.7g

(c) 23.3g

(d) 23.0g

Answer 1

By the low of conservation of mass:

Mass of barium chloride + Mass of sodium sulphate = Mass of sodium chloride + Mass of barium sulphate

i.e.

20.8 g + 14.2 g = 11.7 g + Mass of barium sulphate

or

Mass of barium sulphate = 23.3 g