CaCl2 (aq)-Ca2+ (aq)+2Cl (aq).find no. of ions present in 11 gram of calcium chloride

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Solution

1 mole of compound/ ions = 6.023 x 10²³ or Avagadro's No(N_A)

Molar mass of CaCl₂ = 110.98 g/mol

In 1 mole of calcium chloride = 1 mole of calcium ion + 2 mole of chloride ion = 3 moles of ions

110.98 g of calcium chloride gives = 3 N_A= 3 x 6.023 x 10²³ ions

11 g of calcium chloride gives = (3/110.98) x 11 x 6.023 x 10²³ = 1.7909 x 10²³ ions

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