Calculate number of neutrons present in 12 × 10²⁵ atoms of oxygen (₈O¹⁷). (Given N_A = 6 × 10²³ atoms)

(A) 1800 (B) 1600 (C) 1800 N_A (D) 3200 N_A

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Solution

$1 a t o m o f o x y g e n h a s = 17 - 8 = 9 n e u t r o n s S o 12 \times 10^{25} a t o m s h a s = 9 \times 12 \times 10^{25} n e u t r o n s = 108 \times 10^{25} = 10800 \times 10^{23} = 1793 \times 6 \times 10^{23} = 1793 N_{A} S o o p t i o n C i s c l o s e t o y o u r a n s w e r .$

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