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calculate the...

Question

calculate the equivalent conductance of 1 M h2so4 solution if its conductivity is 2.6x10 to the power -2 /ohm cm

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Solution

We know,
Normality = molarity x number of H⁺ or OH^- ions
Normality of 1M H₂SO₄ = 1 x 2 = 2N

And
$e q u i v a l e n t c o n d u c \tan c e, Λ_{e q} = \frac{c o n d u c t i c i t y (K) x 1000}{N o r m a l i t y} = \frac{2.6 x 10^{- 2} o h m^{- 1} c m^{- 1} x 1000}{2 e q / c m^{3}} = 13 o h m^{- 1} c m^{2} e q^{- 1}$

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