Calculate the force of attractiondue to earth on a child weighing 10 Kg standing on the ground. ( Radius of the earth = 6.4 x 10⁶m ; mass of the earth = 6 x 10²⁴Kg ; and G = 6.7 x 10^-11Nm²/Kg²) ( 98 newtons)

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Solution

we know that
F = GMm / r²
here,
G = 6.67 x 10^-11 Nm²/kg²
M = 6 x 10²⁴ kg
m = 10 kg
r = 6.4 x 10⁶ m
so,
F = ( 6.67 x 10^-11 x 6 x 10²⁴ x 10 ) / ( 6.4 x 10⁶)²
or
= 40.02 x 10¹⁴/ 40.96 x 10¹²
thus, the gravitational force will be
F = 97.8 N ~ 98 N

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Similar questions

A body weighs 100 N on the surface of Earth. What will be the acceleration due to gravity acting on the body at a height of 3400 km above Earth's surface? Taking the mass of Earth $= 6 \times 10^{24} k g$ , Radius of earth $= 6.4 \times 10^{6} m$ and $G = 6.7 \times 10^{- 11} N m^{2} k g^{- 2}$ .

Q. If mass and radius of the Earth are

6.0 \times 10^{24} k g

and

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respectively. Calculate the force exerted by the Earth on a body of mass 1 kg, acceleration of the body of mass 1 kg and acceleration of the Earth in order.
Use

G = 6.67 \times 10^{- 11} N m^{2} k g^{- 2}

Calculate acceleration due to gravity at a height of $2000 k m$ above the Earth's surface. Mass of Earth = $6 \times 10^{24} k g$ , radius of Earth = $6.4 \times 10^{6}$ m and (Gravitational constant, G $= 6.7 \times 10^{- 11} N m^{2} k g^{- 2}$ )

Given mass of earth = $6.4 \times 10^{24}$ kg , radius of earth = $6.4 \times 10^{6}$ m. Calculate the force of attraction experienced by a man of mass 50 kg.

What is the force of gravity on a body of mass 150 kg lying on the surface of the earth?
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Calculate the force of attractiondue to earth on a child weighing 10 Kg standing on the ground. ( Radius of the earth = 6.4 x 106 m ; mass of the earth = 6 x 1024 Kg ; and G = 6.7 x 10-11 Nm2/Kg2) ( 98 newtons)

we know thatF = GMm / r2here,G = 6.67 x 10-11 Nm2/kg2M = 6 x 1024 kgm = 10 kgr = 6.4 x 106 mso,F = ( 6.67 x 10-11 x 6 x 1024 x 10 ) / ( 6.4 x 106 )2or= 40.02 x 1014 / 40.96 x 1012thus, the gravitational force will beF = 97.8 N ~ 98 N

Calculate the force of attractiondue to earth on a child weighing 10 Kg standing on the ground. ( Radius of the earth = 6.4 x 10⁶m ; mass of the earth = 6 x 10²⁴Kg ; and G = 6.7 x 10^-11Nm²/Kg²) ( 98 newtons)

we know that
F = GMm / r²
here,
G = 6.67 x 10^-11 Nm²/kg²
M = 6 x 10²⁴ kg
m = 10 kg
r = 6.4 x 10⁶ m
so,
F = ( 6.67 x 10^-11 x 6 x 10²⁴ x 10 ) / ( 6.4 x 10⁶)²
or
= 40.02 x 10¹⁴/ 40.96 x 10¹²
thus, the gravitational force will be
F = 97.8 N ~ 98 N