CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

calculate the mole fraction of the solute in an aqueous solution containing 18.0g of glucose in 100 g of water

Open in App
Solution

Mole fraction is defined as, concentration in moles equal to the number of moles of a component divided by the total number of moles of a solution.

Thus mole fraction of solute (glucose) = moles of glucose/ total molarity of the solution

Moles of glucose = mass of glucose/ molar mass = 18/180.55 = 0.099
Moles of water = 100/18 = 5.55

Total no. of moles = 0.099 + 5.55 = 5.649

Mole fraction of glucose = 0.099/5.649 = 0.0174

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Abnormal Colligative Properties
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon