Question

calculate the no of ions in 3.06g of molten gram of aluminium oxide

Answer 1

Molecular weight of aluminium oxide (Al₂O₃) is = (27X2 + 16X3) =102

Number of molecule present in 102g aluminium oxide is 6.022X10²³
Number of molecule present in 1g aluminium oxide is 6.022X10²³/102
Number of molecule present in 3.06g aluminium oxide is (6.022X10²³/102)X3.06
=1.8X10²²

Al₂O₃ = 2Al³⁺ + 3O^2-
On dissociation of 1 Al₂O₃ total (2 Al³⁺ and 3 O^2-) = 5 ions produced
1.8X10²² molecule Al₂O₃ will produce 1.8X10²²X5 ions
=9.0X10²² ions