wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

calculate the no of moles for the following

(a) 52g of He {finding moles from mass}

{b}12.046 x 1023 no of atoms [finding mole from the no of particles]

Open in App
Solution

The molar mass of helium is 4 g. Thus the mass of one mole of helium atoms (6.023 X 1023 atoms of helium) is 4g. Hence

4 g of helium atoms = 1 mole of helium atoms

1g of helium atoms = (1/4) moles of helium atoms

52g of helium atoms = (1 X 52)/4 moles of helium atoms

= 13 moles of helium atoms.

6.023 X 1023 atoms of helium = 1 mole of helium atoms

1 atom of helium = 1 / (6.023 X 1023) mole of helium atoms

So 12.046 X 1023 atoms of helium = (12.046 X 1023) / (6.023 X 1023) mole of helium atoms

= 2 moles of helium atoms.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mole and Mass
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon