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Question
calculate the number of atoms in each of the following
(i)52 moles of Ar
(ii)52u of He
(iii)52d of He
calculate the number of atoms in each of the following
(i)52 moles of Ar
(ii)52u of He
(iii)52d of He
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Solution
(1) 52 moles of Ar
We Know
1 mole of Ar = 6.022 X 1023 atoms of Ar
Therefore 52 moles of Ar = 6.022 X 1023 X 52 atoms of Ar
= 3.131 X 1025 atoms of Ar
(2) 52 u of He
The atomic mass of 1 He atom is 4 u. Therefore
4 u of He = 1 atom of He
1 u of He = (1 / 4) atoms of He
52 u of He = (52 / 4) atoms of He
= 13 atoms of He
(3) 52 g of He
The molar mass that is the mass of 6.022 X 1023 atoms of helium is 4g.
Hence 1 mole of He = 4 g of He = 6.022 X 1023 atoms of He
1 g of He = (6.022 X 1023) / 4 atoms of He
52 g of He = (6.022 X 1023X 52 ) / 4 atoms of He
= 7.829 X 1024 atoms of He
(1) 52 moles of Ar
We Know
1 mole of Ar = 6.022 X 1023 atoms of Ar
Therefore 52 moles of Ar = 6.022 X 1023 X 52 atoms of Ar
= 3.131 X 1025 atoms of Ar
(2) 52 u of He
The atomic mass of 1 He atom is 4 u. Therefore
4 u of He = 1 atom of He
1 u of He = (1 / 4) atoms of He
52 u of He = (52 / 4) atoms of He
= 13 atoms of He
(3) 52 g of He
The molar mass that is the mass of 6.022 X 1023 atoms of helium is 4g.
Hence 1 mole of He = 4 g of He = 6.022 X 1023 atoms of He
1 g of He = (6.022 X 1023) / 4 atoms of He
52 g of He = (6.022 X 1023X 52 ) / 4 atoms of He
= 7.829 X 1024 atoms of He
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