calculate the number of electrons passing through an electric lamp in 3 min if current of 300mA passes from it

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Solution

We know,
I = Q/t
Q = It
I =300mA = 0.3 A
t = 3 min = 360s = 180s
=> Q = 0.3180 = 54 C
Q = ne
=> n = Q/e = 54/(1.610^-19)
=> n = 3.375 *10²⁰.

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calculate the number of electrons passing through an electric lamp in 3 min if current of 300mA passes from it

We know,I = Q/tQ = I*tI =300mA = 0.3 At = 3 min = 3*60s = 180s=> Q = 0.3*180 = 54 CQ = ne=> n = Q/e = 54/(1.6*10-19)=> n = 3.375 *1020.

We know,
I = Q/t
Q = It
I =300mA = 0.3 A
t = 3 min = 360s = 180s
=> Q = 0.3180 = 54 C
Q = ne
=> n = Q/e = 54/(1.610^-19)
=> n = 3.375 *10²⁰.