CALCULATE THE NUMBER OF MOLECULES PRESENT IN1- 32 g of so22- 128g of pcl53- 50g of caco3

1 mole = 6.023 x 1023 moleculesSO2 = 32/64 = 0.5 mole = 0.5 x 6.023 x 1023 molecules nbsp; = 3.0115 x 1023 moleculesPCl5 = 128/216.5 = 0.59 mole = 0.59 x 6.02 ...

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Standard XII

Chemistry

Molecular Speeds - Vrms, Vavg, Vmps

CALCULATE THE...

Question

CALCULATE THE NUMBER OF MOLECULES PRESENT IN
1. 32 g of so₂
2. 128g of pcl₅
3. 50g of caco₃

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Solution

1 mole = 6.023 x 10²³ molecules
SO₂ = 32/64 = 0.5 mole = 0.5 x 6.023 x 10²³ molecules
= 3.0115 x 10²³ molecules
PCl₅ = 128/216.5 = 0.59 mole = 0.59 x 6.023 x 10²³ molecules
= 3.56 x 10²³ molecules
CaCO₃ = 50/100 =0.5 mole = 0.5 x 6.023 x 10²³ molecules
= 3.0115 x 10²³ molecules

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CALCULATE THE NUMBER OF MOLECULES PRESENT IN1. 32 g of so22. 128g of pcl53. 50g of caco3

1 mole = 6.023 x 1023 moleculesSO2 = 32/64 = 0.5 mole = 0.5 x 6.023 x 1023 molecules = 3.0115 x 1023 moleculesPCl5 = 128/216.5 = 0.59 mole = 0.59 x 6.023 x 1023 molecules = 3.56 x 1023 moleculesCaCO3 = 50/100 =0.5 mole = 0.5 x 6.023 x 1023 molecules = 3.0115 x 1023 molecules

CALCULATE THE NUMBER OF MOLECULES PRESENT IN
1. 32 g of so₂
2. 128g of pcl₅
3. 50g of caco₃

1 mole = 6.023 x 10²³ molecules
SO₂ = 32/64 = 0.5 mole = 0.5 x 6.023 x 10²³ molecules
= 3.0115 x 10²³ molecules
PCl₅ = 128/216.5 = 0.59 mole = 0.59 x 6.023 x 10²³ molecules
= 3.56 x 10²³ molecules
CaCO₃ = 50/100 =0.5 mole = 0.5 x 6.023 x 10²³ molecules
= 3.0115 x 10²³ molecules