Calculate the time for which a motor pump of 10 HP and efficiency 80% must be switched on,so as to pump 20000kg of water through a vertical height of 20m?

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Solution

Given that,
Efficiency of engine = 80% = 0.8
1 HP = 746 Watt
Power of engine which is used = 7460.8 = 596.8 W
Energy required to lift the water, E = mgh
= 2000010*20 = 4000000 J
Time taken by pump = E/W = 4000000/596.8 = 6702.41 s = 1.862 hours

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