Question

calculate the volume at ntp occupied by 6.022 x 10 power 27 molecules of nitrogen

Answer 1

First, we determine the moles of N₂ by dividing the number of molecules of nitrogen given by Avogadro number

Number of moles of N₂ = $$\begin{gathered} \frac{6.022\times {10}^{27}}{6.022\times {10}^{23}} \\ =10000mol \end{gathered}$$

1 mole of any gas occupies a volume of 24.07L at NTP
10000 moles of a gas occupies a volume of 24.07 $\times$ 10000 = 2.407 $\times$ 10⁵L