calculate the volume at STP occupied by 1021
molecules of Oxygen?
The molar volume that is the volume occupied by one mole of gas is 22.4 L. We know there are 6.022 X 1023 particles of a substance in one mole of that substance. Thus
volume occupied by 6.022 X 1023 molecules of oxygen = 22.4 L
volume occupied by 1 molecule of oxygen = 22.4 / (6.022 X 1023)
volume occupied by 1021 molecules of oxygen = [(22.4 X 1021) / (6.022 X 1023)]
= 3.72 X 10-2 L = 37.2 ml