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Question

calculate the volume at STP occupied by 1021

molecules of Oxygen?

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Solution

The molar volume that is the volume occupied by one mole of gas is 22.4 L. We know there are 6.022 X 1023 particles of a substance in one mole of that substance. Thus

volume occupied by 6.022 X 1023 molecules of oxygen = 22.4 L

volume occupied by 1 molecule of oxygen = 22.4 / (6.022 X 1023)

volume occupied by 1021 molecules of oxygen = [(22.4 X 1021) / (6.022 X 1023)]

= 3.72 X 10-2 L = 37.2 ml


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