calculate the volume occupied by 8gms of sulphur dioxide at stp

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Solution

Molar mass of SO₂ = 32 + (16×2) = 64 g mol^-1
Volume occupied by 32 g of SO₂ = 22.4 L
Volume occupied by 8 g of SO₂ = (22.4 / 32) ×8
= 5.6 L

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calculate the volume occupied by 8gms of sulphur dioxide at stp

Molar mass of SO2 = 32 + (16×2) ​ = 64 g mol-1 ​Volume occupied by 32 g of SO2 = 22.4 L Volume occupied by 8 g of SO2 = (22.4 / 32) ×8 = 5.6 L

Molar mass of SO₂ = 32 + (16×2) = 64 g mol^-1
Volume occupied by 32 g of SO₂ = 22.4 L
Volume occupied by 8 g of SO₂ = (22.4 / 32) ×8
= 5.6 L