Question

Can anyone solve this ques using logarithm??

4.321*0.042*(6.32)^1/2 / 0.72*(0.013)^1/2

Answer 1

$$\begin{gathered} Log4.321+\log 0.042+\frac{1}{2}\log 6.32-[\log 0.72+\frac{1}{2}\log 0.013] \\ 0.635+(-1.377)+\frac{1}{2}\times 0.800-[-0.143+\frac{1}{2}\times (-1.886) \\ -0.742+0.400-[-0.143-0.943] \\ -0.342+1.086=0.744 \\ takeanti\log of0.744withbase10 \\ 5.546 \end{gathered}$$