Question

Can i get an explained calculation on the following question

Find three consecutive natural numbers such that the sum of the first and the second is fifteen more than the third.

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{three}\mathrm{consecutive}\mathrm{natural}\mathrm{numbers}\mathrm{are}: \\ x,x+1\mathrm{and}x+2 \\ \mathrm{Now},\mathrm{according}\mathrm{to}\mathrm{question}, \\ \mathrm{first}\mathrm{number}+\mathrm{second}\mathrm{number}=\mathrm{third}\mathrm{number}+15 \\ \Rightarrow x+\left(x+1\right)=\left(x+2\right)+15 \\ \Rightarrow x+x+1=x+2+15 \\ \Rightarrow 2x+1=x+17 \\ \Rightarrow 2x-x=17-1 \\ \Rightarrow x=16 \\ \mathrm{So},\mathrm{consecutive}\mathrm{natural}\mathrm{numbers}\mathrm{are}: \\ 16,17\mathrm{and}18 \end{gathered}$$