ch3-ch2-oh---alkaline kmno4+heat--------------- ch3-cooh
in the above given reaction alkaline kmno4 reacts as-____________________

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Solution

CH₃-CH₂-OH + alkaline KMnO₄ $\overset{∆}{\to}$ CH₃-COOH
In the above given reaction alkaline KMnO₄ reacts as oxidizing agent. It supplies [O] to alcohol(ethanol) which is then converted to acid (ethanoic acid).

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{CH}_{3} - {CH}_{2} - OH {Alkaline KMnO}_{4} + Heat - ------------- \to {CH}_{3} - COOH

{KMnO}_{4}

C H_{3} - C H_{2} - O H a l k a l i n e K M n O_{4} + H e a t - ------------- \to C H_{3} - C O O H

K M n O_{4}

In this reaction alkaline $K M n O_{4}$ behaves as:

$C H_{3} - C H_{2} - O H a l k a l i n e K M n O_{4} + h e a t - -------------- \to {C H}_{3} - C O O H$

{CH}_{3} - {CH}_{2} - OH {Alkaline KMnO}_{4} + Heat - ------------- \to {CH}_{3} - COOH

{KMnO}_{4}

C H_{3} C H_{2} O H A l k a l i n e K M n O 4 + H e a t - ------------- \to C H_{3} C O O H

K M n O_{4}

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