p - character in ${s p}^{2}$ hybridization is:

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Solution

The correct option is C

Here:

1s orbital + 1p orbital $\Rightarrow$ 2 $s p$ hybrid orbitals

1s orbital + 2p orbital $\Rightarrow$ 3 ${s p}^{2}$ hybrid orbitals

1s orbital + 3p orbital $\Rightarrow$ 4 ${s p}^{3}$ orbital (hybrid)

So, whenever we are get ${s p}^{2}$ hybridization, we get three ${s p}^{2}$ hybrid orbitals.

p - charcter = $\frac{N u m b e r o f p - o r b i t a l i n v o l v e d i n h y b r i d i z a t i o n}{N u m b e r o f h y b r i d o r b i t a l s}$

p - charcter = $\frac{2}{3}$

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Similar questions

s - character in ${s p}^{3}$ hybridization is:

s - character in ${s p}^{3}$ hybridization is

${s p}^{2}$ hybrid orbitals have equal s and p character.

s p^{2}

{s p}^{2}

s

p

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