Chlorine is prepared in the lab by treating with MnO2 with aqueous HCl
How many grams of HCl reacts with 5g of MnO2?

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Solution

Reaction is
4HCl + MnO₂ → 2H₂O + MnCl₂ + Cl₂

amount of HCl = 4 ×36.5=146g
amount of MnO₂= 1×87= 87g
where 36.5g is molar mass of HCl
and 87 g is molar mass of MnO_2.
According to reaction:

146 g of HCl react with 87 g of MnO₂
let x g of HCl is required to react with 5 g of MnO₂ to form MnCl₂ and Cl_2.
so using unitary method to calculate the amount of HCl

x = $\frac{5 \times 146}{87}$
x= 8.391 g

therefore, 8.391 g of HCl will react with 5g of MnO_2.

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