Question

Complete the entries in the third column of the table.

S. No.	Equation	Value of variable	Equation satisfied Yes/No
(a)	10y = 80	y = 10	-
(b)	10y = 80	y = 8	-
(c)	10y = 80	y = 5	-
(d)	4l = 20	l = 20	-
(e)	4l = 20	l = 80	-
(f)	4l = 20	l = 5	-
(g)	b + 5 = 9	b =5	-
(h)	b + 5 = 9	b = 9	-
(i)	b + 5 = 9	b = 4	-
(j)	h − 8 = 5	h = 13	-
(k)	h − 8 = 5	h = 8	-
(l)	h − 8 = 5	h = 0	-
(m)	p + 3 = 1	p = 3	-
(n)	p + 3 = 1	p = 1	-
(o)	p + 3 = 1	p = 0	-
(p)	p + 3 = 1	P = − 1	-
(q)	p + 3 = 1	P = − 2	-

Answer 1

(a) 10y = 80

y = 10 is not a solution to the given equation because fory = 10,

10y = 10 × 10 = 100, and not 80

(b) 10y = 80

y = 8 is a solution to the given equation because for y= 8,

10y = 10 × 8 = 80 and hence, the equation issatisfied.

(c) 10y = 80

y = 5 is not a solution to the given equation because for y= 5,

10y = 10 × 5 = 50, and not 80

(d) 4l = 20

l = 20 is not a solution to the given equation because forl = 20,

4l = 4 × 20 = 80, and not 20

(e) 4l = 20

l = 80 is not a solution to the given equation because forl = 80,

4l = 4 × 80 = 320, and not 20

(f) 4l = 20

l = 5 is a solution to the given equation because for l= 5,

4l = 4 × 5 = 20 and hence, the equation is satisfied.

(g) b + 5 = 9

b = 5 is not a solution to the given equation because for b= 5,

b + 5= 5 + 5 = 10, and not 9

(h) b + 5 = 9

b = 9 is not a solution to the given equation because for b= 9,

b + 5= 9 + 5 = 14, and not 9

(i) b + 5 = 9

b = 4 is a solution to the given equation because for b= 4,

b + 5= 4 + 5 = 9 and hence, the equation is satisfied.

(j) h − 8 = 5

h = 13 is a solution to the given equation because for h= 13,

h − 8= 13 − 8 = 5 and hence, the equation issatisfied.

(k) h − 8 = 5

h = 8 is not a solution to the given equation because for h= 8,

h − 8= 8 − 8 = 0, and not 5

(l) h − 8 = 5

h = 0 is not a solution to the given equation because for h= 0,

h − 8= 0 − 8 = −8, and not 5

(m) p + 3 = 1

p = 3 is not a solution to the given equation because for p= 3,

p + 3= 3 + 3 = 6, and not 1

(n) p + 3 = 1

p = 1 is not a solution to the given equation because for p= 1,

p + 3= 1 + 3 = 4, and not 1

(o) p + 3 = 1

p = 0 is not a solution to the given equation because for p= 0,

p + 3= 0 + 3 = 3, and not 1

(p) p + 3 = 1

p = −1 is not a solution to the given equationbecause for p = −1,

p + 3= −1 + 3 = 2, and not 1

(q) p + 3 = 1

p = −2 is a solution to the given equation becausefor p = −2,

p + 3= − 2 + 3 = 1 and hence, the equation issatisfied.