Question

Compute the heat generated while transforing 96,000 coulombs of charge in one hour through a potential difference of 50 V.

Answer 1

I=Q/t

I=current,Q=charge in coulomb,t=time in sec

time given 1 hour=3600 seconds

I=96000/3600 =26.66 A

Heat generated=V×I×t

50×26.66×3600=4800 kjoule

in watt 4800/3600=1.33 kw