Construct a triangle XYZ in which Y = 30, Z = 90 and XY + YZ + ZX = 11 cm.
After constructing a triangle given its base , base angle and sum or difference of other 2 sides , Will we get the correct measurement of 2 sides?

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Solution

Steps of Construction:

a) Draw AB = XY+YZ+ZX = 11 cm.
$b) D r a w ∠ P A B = 30 ° a n d ∠ Q B A = 90 ° . c) D r a w a n g l e b i s e c t o r s f o r ∠ P A B a n d ∠ Q B A, l e t t h e s e i n t e r s e c t a t X . d) D r a w p e r p e n d i c u l a r b i s e c t o r f o r X A a n d Y B w h i c h c u t s A B a t Y a n d Z r e s p e c t i v e l y . e) J o i n X Y a n d Y Z . T h i s i s r e q u i r e d t r i a n g l e X Y Z .$

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Similar questions

Construct a triangle XYZ in which $∠ Y = 30^{\circ}, ∠ Z = 90^{\circ} a n d X Y + Y Z + Z X = 11.$

Construct a triangle $X Y Z$ in which $∠ Y = 30^{\circ},$ $∠ Z = 90^{\circ}$ and $X Y + Y Z + Z X = 11 c m .$

∠ Y

30^{0}

∠ Z

90^{0}

X Y Z

∠ Y = 30^{o}, ∠ Z = 90^{o}

X Y + Y Z + Z X = 11 c m

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.

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