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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Compound Angles
cot(90-tita)s...
Question
cot(90-tita)sin(90-tita)/ sin tita + cot40/tan50 - (cos square20 + cos square70). evaluate
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Solution
cot
90
°
-
θ
sin
90
°
-
θ
sin
θ
+
cot
40
°
tan
50
°
-
cos
2
20
°
+
cos
2
70
°
=
tan
θ
.
cos
θ
sin
θ
+
cot
90
°
-
50
°
tan
50
°
-
cos
2
90
°
-
70
°
+
cos
2
70
°
=
sin
θ
.
cos
θ
sin
θ
.
cos
θ
+
tan
50
°
tan
50
°
-
sin
2
70
°
+
cos
2
70
°
=
1
+
1
+
1
=
3
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